Thursday 4th September
TODAY WE ARE
LEARNING ABOUT
 How is the cross-sectional area of a zone of inhibition calculated?
TODAY'S
KEY WORDS ARE
  • _r__  
  • P_p_l_t__n  
  • C_ll  d_v_s__n  
  • St_nd_rd  f_rm  
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    Memory Anchor:

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    • Super Challenge:

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    Key Questions:

    1. (Biology only) How would the cross-sectional areas of colonies or clear areas around colonies be calculated? How can this be used to calculate the cross-sectional area for a radius of 0.25 mm?
      • (Biology only) Cross-sectional areas of colonies or clear areas around colonies are calculated using 'pie-r-squared'. For a cross-sectional area with radius 0.25mm: 3.14 x (0.25-squared) = 0.20mm (2d.p.)
    2. (Biology only) How is the number of bacteria in a population calculated after a certain time if given the mean division time?
      • (Biology only) 2 to the power of the number of generations x initial number of bacteria.
    3. (Biology only) What is the population of bacteria, which have a mean division time of 5-minutes, after 45-minutes if starting with just 5 bacteria? How would this answer be shown using standard form?
      • (Biology only) The population of bacteria, which have a mean division time of 5-minutes, after 45-minutes if starting with just 5 bacteria is: 45 divided by 5 = 9, so 2 to the power of 9 multiplied by 5 = 2560 bacteria. In standard form this is written as: 2.56 x 10 to the power 3 bacteria.