Friday 5th September
TODAY WE ARE
LEARNING ABOUT
 How do you calculate reacting masses?
TODAY'S
KEY WORDS ARE
  • B_l_nc_ng  _q__t__ns
  • R__ct_nts
  • Pr_d_cts
  • M_ss
    		•

    Memory Anchor:

    MgCI2 + H2 shows that one mole of magnesium reacts with two moles of hydrochloric acid to produce one mole of magnesium chloride and one mole of hydrogen gas. [SepOnly] => 0 [HTOnly] => 1 [KeyWord] => [MemoryAnchor] => [Activity] => [Equipment] => [Question] => (HT only)In the following equation: Mg 2HCI --> MgCI2 H2 What is the ratio of magnesium (Mg) atoms react in comparison to that of hydrochloric acid (HCl)? [Answer] => 1:2 This is because chemical equations can be interpreted in terms of moles. Mg + 2HCI --> MgCI2 + H2 The equation shows that one mole of magnesium (Mg) reacts with two moles of hydrochloric acid (HCl) [Mislead1] => [Mislead2] => [Mislead3] => [Module] => C1.5.06 [Ordering] => 20 [Method] => [GoFurther] => [Quiz] => [Flag] => 0 [Code] => C1.5.06 [Title] => How do you calculate reacting masses? ) [2] => Array ( [RowID] => 12451 [KS] => 4 [PosCode] => [SpecCode] => 4.3.2.2.c [Point] => Students should be able to calculate the masses of substances shown in a balanced symbol equation [SepOnly] => 0 [HTOnly] => 1 [KeyWord] => [MemoryAnchor] => [Activity] => [Equipment] => [Question] => (HT only)CaCO3 2HCl ---> CaCl2 CO2 H2O Use the above equation to determine the mass of carbon dioxide produced if you react 10g of calcium carbonate with an excess of hydrochloric acid? [Answer] => 4.4g of CO2 is produced [Mislead1] => [Mislead2] => [Mislead3] => [Module] => C1.5.06 [Ordering] => 30 [Method] => [GoFurther] => [Quiz] => [Flag] => 0 [Code] => C1.5.06 [Title] => How do you calculate reacting masses? ) [3] => Array ( [RowID] => 12451 [KS] => 4 [PosCode] => [SpecCode] => 4.3.2.2.d [Point] => Students should be able to calculate the masses of reactants and products from the balanced symbol equation and the mass of a given reactant or product. [SepOnly] => 0 [HTOnly] => 1 [KeyWord] => [MemoryAnchor] => [Activity] => [Equipment] => [Question] => (HT only)Calculate the mass of iron produced when 32g of iron (III) oxide is completely reduced by aluminium. The reaction is shown in the symbol equation: Fe2O3 2Al ? 2Fe Al2O3 [Answer] => When 32g of iron (III) oxide is reduced by aluminium 22.4g of iron is produced [Mislead1] => [Mislead2] => [Mislead3] => [Module] => C1.5.06 [Ordering] => 40 [Method] => [GoFurther] => [Quiz] => [Flag] => 0 [Code] => C1.5.06 [Title] => How do you calculate reacting masses? ) [4] => Array ( [RowID] => 12451 [KS] => 4 [PosCode] => [SpecCode] => 4.3.2.3.a [Point] => The balancing numbers in a symbol equation can be calculated from the masses of reactants and products by converting the masses in grams to amounts in moles and converting the numbers of moles to simple whole number ratios. [SepOnly] => 0 [HTOnly] => 1 [KeyWord] => [MemoryAnchor] => [Activity] => [Equipment] => [Question] => (HT only)How can you use the massess of reactants and products to balance a symbol equation? [Answer] => The balancing numbers in a symbol equation can be calculated from the masses of reactants and products by converting the masses in grams to amounts in moles and converting the numbers of moles to simple whole number ratios. [Mislead1] => [Mislead2] => [Mislead3] => [Module] => C1.5.06 [Ordering] => 50 [Method] => [GoFurther] => [Quiz] => [Flag] => 0 [Code] => C1.5.06 [Title] => How do you calculate reacting masses? ) [5] => Array ( [RowID] => 12451 [KS] => 4 [PosCode] => [SpecCode] => 4.3.2.3.b [Point] => Students should be able to balance an equation given the masses of reactants and products. [SepOnly] => 0 [HTOnly] => 1 [KeyWord] => [MemoryAnchor] => [Activity] => [Equipment] => [Question] => (HT only) Reactants Sb = 488g Cl2 = 426g Products SbCl3= 914g Complete a symbol equation for the reaction above using the masses to balance the equation. [Answer] => 2Sb + 3Cl2 ---> 2SbCl3 [Mislead1] => [Mislead2] => [Mislead3] => [Module] => C1.5.06 [Ordering] => 60 [Method] => [GoFurther] => [Quiz] => [Flag] => 0 [Code] => C1.5.06 [Title] => How do you calculate reacting masses? ) [6] => Array ( [RowID] => 12451 [KS] => 4 [PosCode] => [SpecCode] => 4.3.2.3.c [Point] => Students should be able to change the subject of a mathematical equation. [SepOnly] => 0 [HTOnly] => 1 [KeyWord] => [MemoryAnchor] => [Activity] => [Equipment] => [Question] => (HT only)How do you rearrange the moles equation to find the relative formulat mass? Moles = mass / RFM [Answer] => The moles equation can be rearranged to find RFM = mass / moles [Mislead1] => [Mislead2] => [Mislead3] => [Module] => C1.5.06 [Ordering] => 70 [Method] => [GoFurther] => [Quiz] => [Flag] => 0 [Code] => C1.5.06 [Title] => How do you calculate reacting masses? ) ) -->
    YOU WILL SHOW
    YOUR LEARNING BY...

    • Super Challenge:

      Stretch:

      Challenge:

    Key Questions:

    1. (HT only)Balance the equation and calculate the mass of the reactants and products of the balanced symbol equation: H2O2 --> H20 02
      • 2H2O2 --> 2H20 02 The mass of the reactants is 68, the mass of the reactants is also 68
    2. (HT only)In the following equation: Mg 2HCI --> MgCI2 H2 What is the ratio of magnesium (Mg) atoms react in comparison to that of hydrochloric acid (HCl)?
      • 1:2 This is because chemical equations can be interpreted in terms of moles. Mg + 2HCI --> MgCI2 + H2 The equation shows that one mole of magnesium (Mg) reacts with two moles of hydrochloric acid (HCl)
    3. (HT only)CaCO3 2HCl ---> CaCl2 CO2 H2O Use the above equation to determine the mass of carbon dioxide produced if you react 10g of calcium carbonate with an excess of hydrochloric acid?
      • 4.4g of CO2 is produced
    4. (HT only)Calculate the mass of iron produced when 32g of iron (III) oxide is completely reduced by aluminium. The reaction is shown in the symbol equation: Fe2O3 2Al ? 2Fe Al2O3
      • When 32g of iron (III) oxide is reduced by aluminium 22.4g of iron is produced
    5. (HT only)How can you use the massess of reactants and products to balance a symbol equation?
      • The balancing numbers in a symbol equation can be calculated from the masses of reactants and products by converting the masses in grams to amounts in moles and converting the numbers of moles to simple whole number ratios.
    6. (HT only) Reactants Sb = 488g Cl2 = 426g Products SbCl3= 914g Complete a symbol equation for the reaction above using the masses to balance the equation.
      • 2Sb + 3Cl2 ---> 2SbCl3
    7. (HT only)How do you rearrange the moles equation to find the relative formulat mass? Moles = mass / RFM
      • The moles equation can be rearranged to find RFM = mass / moles