Lesson Plan: B1.1.08


LESSON PLAN
Teacher Subject Period Date Year Ability LSA/Other Support
Science

Context and
Landmark
Assessment		 B1.1.08
Landmark Assessment: Progress Observation Opportunity
Remember to have high expectations
Lesson Title: Today we are learning about
How is the cross-sectional area of a zone of inhibition calculated?
Remember to check for PROGRESS
Focus on Knowledge, Skills and Understanding
Success Criteria: You will show your learning by...
  1. (Biology only) Students should be able to calculate cross-sectional areas of colonies or clear areas around colonies using πr².
  2. (Biology only) Students should be able to calculate the number of bacteria in a population after a certain time if given the mean division time.
  3. (Biology only) Students should be able to express the answer in standard form.
Think about how you can match the needs of ALL students
Keywords:
  • Standard form: a system of writing very large or very small numbers to make it more manageable. (1)
  • Cell division: the division of a cell into two daughter cells with the same genetic material. (1)
  • Population: a community of animals, plants, or humans among whose members interbreeding occurs. (1)
  • Area: the total surface of an object. (1)
Links: Literacy, Numeracy, SMSC, British values
Memory Anchor:

AFL/Key Questions:
  1. (Biology only) How would the cross-sectional areas of colonies or clear areas around colonies be calculated? How can this be used to calculate the cross-sectional area for a radius of 0.25 mm?
    (Biology only) Cross-sectional areas of colonies or clear areas around colonies are calculated using 'pie-r-squared'. For a cross-sectional area with radius 0.25mm: 3.14 x (0.25-squared) = 0.20mm (2d.p.)
  2. (Biology only) How is the number of bacteria in a population calculated after a certain time if given the mean division time?
    (Biology only) 2 to the power of the number of generations x initial number of bacteria.
  3. (Biology only) What is the population of bacteria, which have a mean division time of 5-minutes, after 45-minutes if starting with just 5 bacteria? How would this answer be shown using standard form?
    (Biology only) The population of bacteria, which have a mean division time of 5-minutes, after 45-minutes if starting with just 5 bacteria is: 45 divided by 5 = 9, so 2 to the power of 9 multiplied by 5 = 2560 bacteria. In standard form this is written as: 2.56 x 10 to the power 3 bacteria.
Identify questions for high, middle, low and identify questioning techniques- Challenge questions

Learning Phases/Episodes
Think about how you can match the needs of ALL students
Differentiation: AGT, SEND, LLL, Disadvantaged
Remember to check for PROGRESS
Starter Activity Differentiation and Challenge question/task
  • Students to copy and complete the keywords.
  • Teacher reveals missing letters; Students correct mistakes;
  • Discuss the scientific meanings of the words.
  • Students to write down the definitions of the most important / new keywords.
  • Discuss the 'Memory Anchor'.
    • What does it show?
    • How does it relate to the what we are learning about today (title)?
Think about PACE – Develop, consolidate and deepen knowledge, skills and understanding
Teacher or Student lead? Differentiation and Challenge question/task
Progress Check Extension
Remember to give time to apply knowledge, skills and understanding
Teacher or Student lead? Differentiation and Challenge question/task
Progress Check Extension

Teacher or Student lead? Differentiation and Challenge question/task
Progress Check Extension

Teacher or Student lead? Differentiation and Challenge question/task
Progress Check Extension


Plenary Differentiation and Challenge question/task
  • Students to answer the 'Key Questions' with learning partners.
Progress Check
  • Teacher to reveal and discuss the answers to the questions.
 Extension
  • What have learnt about the 'Big Ideas' today?

Homework Differentiation and Challenge question/task