Lesson Plan: C1.6.09
LESSON
PLAN
Teacher
Subject
Period
Date
Year
Ability
LSA/Other Support
Science
Context andLandmarkAssessment
C1.6.09
Landmark Assessment: Progress Observation Opportunity
Remember to have high expectations
Lesson Title:
Today we are learning about
What can we learn from titrations?
Remember to check for PROGRESSFocus on Knowledge, Skills and Understanding
Success Criteria:
You will show your learning by...
Students should be able to: - describe how to carry out titrations using strong acids and strong alkalis only (sulfuric, hydrochloric and nitric acids only) to find the reacting volumes accurately
(MS) (HT Only) calculate the chemical quantities in titrations involving concentrations in mol/dm3 and in g/dm3.
(MS) (HT only) determination of the concentration of one of the solutions in mol/dm3 and g/dm3 from the reacting volumes and the known concentration of the other solution.
Think about how you can match the needs of ALL students
Keywords:
mole
: The mole is the unit of measurement for amount of a substance
(1)
Concentration
: the relative amount of a particular substance contained within a solution or mixture or in a particular volume of space.
(1)
EW_Describe how to carry out titrations using strong acids and strong alkalis only (sulfuric, hydrochloric and nitric acids only) to find the reacting volumes accurately_
(1)
Links:
Literacy, Numeracy, SMSC, British values
Memory Anchor:
AFL/Key Questions:
A sample of vinegar contains 0.1 mol/dm3 ethanoic acid. What is its concentration in g/dm3? (The relative formula mass, Mr, of ethanoic acid is 60)
concentration in g/dm3 = concentration in g/dm3 ? Mr concentration = 0.1 ? 60 = 6 g/dm3 Answer 6 g/dm3
25 cm3 of dilute hydrochloric acid is neutralised by 20 cm3 of 0.5 mol/dm3 sodium hydroxide. What is the concentration of the hydrochloric acid?
Step 1: Convert volumes to dm3 25 cm3 of HCl = 25 /1000 = 0.025 dm3 20 cm3 of NaOH = 20 / 1000 = 0.020 dm3 Step 2: Determine the number of moles of sodium hydroxide moles of NaOH = concentration ? volume moles of NaOH = 0.5 x 0.020 = 0.010 mol Step 3: Work out the number of moles of acid using the balanced equation HCl(aq) NaOH(aq) ? NaCl(aq) H2O(l) In this reaction, one mole of HCl reacts with one mole of NaOH. This is a 1:1 ratio. Therefore, in our titration, 0.010 mol of NaOH must neutralise 0.010 mol of HCl. Step 4: Calculate the concentration of the acid concentration of HCl = number of moles / volume concentration of HCl = 0.010 / 0.025 = 0.4 mol/dm3 Answer The concentration of the HCl is 0.4 mol/dm3.
Identify questions for high, middle, low and identify questioning techniques- Challenge questions
Learning Phases/Episodes
Think about how you can match the needs of ALL students
Differentiation:
AGT, SEND, LLL, Disadvantaged
Remember to check for PROGRESS
Starter Activity
Differentiation and Challenge question/task
Students to copy and complete the keywords.
Teacher reveals missing letters; Students correct mistakes;
Discuss the scientific meanings of the words.
Students to write down the definitions of the most important / new keywords.
Discuss the 'Memory Anchor'.
What does it show?
How does it relate to the what we are learning about today (title)?
Think about PACE – Develop, consolidate and deepen knowledge, skills and understanding
Teacher or Student lead?
Differentiation and Challenge question/task
Progress Check
Extension
Remember to give time to apply knowledge, skills and understanding
Teacher or Student lead?
Differentiation and Challenge question/task
Progress Check
Extension
Teacher or Student lead?
Differentiation and Challenge question/task
Progress Check
Extension
Teacher or Student lead?
Differentiation and Challenge question/task
Progress Check
Extension
Plenary
Differentiation and Challenge question/task
Students to answer the 'Key Questions' with learning partners.
Progress Check
Teacher to reveal and discuss the answers to the questions.
Extension
What have learnt about the 'Big Ideas' today?
Homework
Differentiation and Challenge question/task